Question #cfb72

1 Answer
Jun 24, 2015

#y=2/7x+1#

Explanation:

To write an equation for a line, we are going to use the slope and y-intercept.

Looking at the equation of the existing line: #y = 2/7 x -3#, we see that it is in slope-intercept form ( #y=mx+b# ) where #m#, the slope, is #2/7#.

We're looking for a line that is parallel to this line; for this second line to be parallel, it must have the same slope.

If we know both the slope and a point that the line goes through, we can find the y-intercept.

Starting with:
#y=mx+b#

Substitute our slope, #color(orange)[2/7]#:
#y=color(orange)[2/7]x+b#

And our point, #(color(green)7,color(blue)3)#:
#color(blue)3=2/7*color(green)7+b#

Now we can simplify - first cancel out the 7s:
#3 = 2 + b#

Subtract both sides by 2:
#3 - 2 = b#
#1 = b#

Now we have all the information we need to write an equation for our new line. To write the equation for this line, we can use the familiar slope-intercept form.

Starting with our formula:
#y=mx+b#

Substitute our slope, #color(orange)[2/7]# and y-intercept #b#, #color(purple)1#:
#y=color(orange)[2/7]x+color(purple)1#

...and we're done!

It's always good to double check our work - one way to do that is to graph both equations. We can also plug our #(x,y)# of #(color(green)7,color(blue)3)# into our equation to make sure it actually passes through that point (since we're confident that our slope is correct). If we do that and simplify, we'll see that:
#color(blue)3=2/7*color(green)7+1#
#3 = 2+1#
#3 = 3#