Question #75ba1

1 Answer
Jun 28, 2015

Answer:

Here's how you'd go about solving this one.

Explanation:

You know that your object starts from rest, which means that tis initial velocity will be equal to zero.

Moreover, it has an uniform acceleration of #4 "m/s"^2#. To determine its displacement, you can use this equation

#d = v_0 * t + 1/2 * a * t^2#, where

#t# - the object's time of travel;
#a# - its acceleration.

In your case, you have

#d = underbrace(v_0)_(color(blue)("=0")) * t + 1/2 * a * t^2 = 1/2 * a * t^2#

Point (1)

After 5 seconds, the object's displacement will be

#d = 1/2 * 4"m"/cancel("s"^2) * 5^2cancel("s"^2) = color(green)("50 m")#

Point (2)

To determine how much the object travelled in the #5^("th")# second of movement, you need to subtract the distance it travelled after 5 seconds from the distance it travelled after 6 seconds.

#Deltad_(5,6) = d_6 - d_5#

#d_6 = 1/2 * 4"m"/cancel("s"^2) * 6^2cancel("s"^2) = "72 m"#

#d_5 = "50 m"#

#Deltad_(5,6) = 72 - 50 = color(green)("22 m")#

Point (3)

The same method can be used to determine the distance the object travelled in its #8^("th")# second of movement.

#Deltad_(8,9) = d_9 - d_8#

#d_9 = 1/2 * 4"m"/cancel("s"^2) * 9^2cancel("s"^2) = "162 m"#

#d_8 = 1/2 * 4"m"/cancel("s"^2) * 8^2cancel("s"^2) = "128 m"#

Therefore,

#Deltad_(8,9) = 162 - 128 = color(green)("34 m")#