Question #60683

1 Answer
Jul 1, 2015

Answer:

(note: #y# is equivalent to #p(x)# for this question)
y-intercept #=6#
x-intercepts #=-2 and -3#

Explanation:

The y-intercept is the value of y (or as in the question #p(x)# where the graph of the equation crosses the y-axis. This is the point on the graph where #x=0# (since #x=0# for all points on the y-axis).
#color(white)("XXXX")##y = (0)^2 + 5(0) + 6 = 6#

The x-intercepts similarly are the values of #x# when # y# (or #p(x)#) #=0#
#color(white)("XXXX")##0 = x^2+5x+6#

#color(white)("XXXX")##(x+2)(x+3) = 0#

#color(white)("XXXX")##rArr x=-2#
#color(white)("XXXX")#or #x=-3#