# Question #edc96

Jul 1, 2015

$0.14 \text{g}$

#### Explanation:

The number of moles $O = \frac{0.08}{A} _ r = \frac{0.08}{16} = 0.005$

Since the formula is ${N}_{2} O$ the number of moles of $N = 0.005 \times 2 = 0.01$

The ${A}_{r}$ of $N = 14$.

So mass $N = 14 \times 0.01 = 0.14 \text{g}$

(Approx ${A}_{r}$ values used).