Question

Question #f7d59

Answer 1

(If we ignore the equation)
Looking at the plot of the given data points, we can estimate that
`y=0` when `x =-1/2` and when `x = 2 1/3`

Explanation:

(see image below for a rough plot of the given data)

We can see that the curve crosses the X-axis (`y=0`) at about `x=-1/2` and again at about `x = 2 1/3`

Note that the given data points do not match the given equation
(?????)

However, we could solve this equation analytically:
`x^2-2x-1 = x+3`

`rarr` `color(white)("XXXX")` `x^2-3x-4 = 0`

then using the quadratic formula
`color(white)("XXXX")` `x = (-b+-sqrt(b^2-4ac))/(2a)`
we would have
`color(white)("XXXX")` `x = (3+-sqrt(9+16))/2 = (3+-5)/2`

`color(white)("XXXX")` `x = 4 or x = -1`