# Question 3a6f8

Jul 29, 2015

Empirical formula: ${C}_{10} {H}_{18} O$

#### Explanation:

You know that 100 g of eucalyptol contains 6.484 moles of carbon, 11.67 moles of hydrogen, and 0.6481 moles of oxygen.

To determine the compound's empirical formula, all you need to do is figure out what the mole ratios of these elements are.

To do that, divide all three values you got by the smallest one to get

"For C": (6.484color(red)(cancel(color(black)("moles"))))/(0.6481color(red)(cancel(color(black)("moles")))) = 10

"For H": (11.67color(red)(cancel(color(black)("moles"))))/(0.6481color(red)(cancel(color(black)("moles")))) = 18

"For O": (0.6481color(red)(cancel(color(black)("moles"))))/(0.6481color(red)(cancel(color(black)("moles")))) = 1#

This means that eucalyptol's empirical formula is

$\textcolor{g r e e n}{{C}_{10} {H}_{18} O}$