# Question #d7002

Aug 4, 2015

I found: c. $14 \frac{m}{s}$

#### Explanation:

Have a look:

Aug 4, 2015

(c). $14 \text{m/s}$

#### Explanation:

${v}^{2} = {u}^{2} + 2 a s$

In this case the acceleration vector at an angle of ${60}^{0}$ will be equal to $g \cos 60$

So:

${v}^{2} = 0 + 2 \times 9.8 \cos 60 \times 20$

${v}^{2} = 40 \times 9.8 \times \frac{1}{2}$

${v}^{2} = 196$

$v = 14 \text{m/s}$

The mass is irrelevant to the question.