Question #d7002

2 Answers
Aug 4, 2015

Answer:

I found: c. #14 m/s#

Explanation:

Have a look:
enter image source here

Aug 4, 2015

Answer:

(c). #14"m/s"#

Explanation:

upload.wikimedia.org

#v^2=u^2+2as#

In this case the acceleration vector at an angle of #60^0# will be equal to #gcos60#

So:

#v^2=0+2xx9.8cos60xx20#

#v^2=40xx9.8xx1/2#

#v^2=196#

#v=14"m/s"#

The mass is irrelevant to the question.