Question #fedfc

1 Answer
Bill K.
Aug 13, 2015

#3/4#

Explanation:

I assume you meant #(64/27)^(-1/3)#.

By a property of exponents, #(64/27)^(-1/3)=(27/64)^(1/3)#. Now #x^{1/3}=root{3}(x)#. Hence, #(27/64)^(1/3)=root{3}(27/64)=3/4# since #(3/4)^3=(3^3)/(4^3)=27/64#.

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