# Question #b9611

##### 1 Answer

That depends on how many grams of 20-carat gold you have.

#### Explanation:

Now, since you didn't provide an actual mass of 20-carat gold, I'll use

Now, the first thing that you need to do is figure out how much gold you have in

As you can see, 20-carat gold contains **83.33%** gold by weight. This means that a *100-g* sample of 20-carat gold will contain **83.33 g** of pure gold.

In your case,

#xcolor(red)(cancel(color(black)("g 20-carat"))) * "83.33 g gold"/(100color(red)(cancel(color(black)("g 20-carat")))) = (0.833 * x) " grams of gold"#

Use gold's *molar mass*, which tells you what the mass of **1 mole** of gold is, to determine how many moles of gold you'd get in that mass

#(0.833 * x)color(red)(cancel(color(black)("g gold"))) * "1 mole Au"/(196.97color(red)(cancel(color(black)("g gold")))) = (0.00423 * x)" moles Au"#

To get how many atoms of gold you'd get in that many moles, use the fact that *1 mole* of any element contains exactly **Avogadro's number**.

In your case, that many moles would contain

#(0.00423 * x)color(red)(cancel(color(black)("moles Au"))) * (6.022 * 10^(23)"atoms of Au")/(1color(red)(cancel(color(black)("mole Au")))) = (2.55 * x) * 10^(21)"atoms of Au"#

To get the actual answer, simply replace

**ADDENDUM**

For **20 g** of 20-carat gold, you would get

#2.55 * 20 * 10^(21) = 5.1 * 10^(22)"atoms of Au"#