If #F(x)=(33-x)/(x-1)#, what is #F(9)#?

1 Answer
Sep 30, 2015

#F(9)# is the value of the function #F(x)# when #x# is replaced in the expression for #F(x)# with #9# and the expression is simplified.

Explanation:

For example if
#color(white)("XXX")F(x) = (33-x)/(x-1)#
then
#color(white)("XXX")F(9)=(33-9)/(9-1) = 24/8 = 3#

Note that although I have used #x# as the variable in the defining expression for #F(x)# any variable could have been used. For the given example
#color(white)("XXX")F(x)=(33-x)/(x-1)#
is exactly equivalent to
#color(white)("XXX")F(t)=(33-t)/(t-1)#
and
#color(white)("XXX")F(9)# would still have the same value.