Question #53a26

1 Answer
Sep 15, 2015

The balanced equation is as follows:

Explanation:

IO3 is the oxidizing agent, it gets reduced into I2.
I is a reducing agent, it gets oxidized also into I2.

You should write two half equations:
Reduction: 2IO3 + 12H+ + 10e ----------> I2 + 6H2O
Oxidation: 2I ----------> I2 + 2e

You should multiply the oxidation half equation by 5 and sum both half equations to get:
Reduction: 2IO3 + 12H+ + 10e ----------> I2 + 6H2O
Oxidation: x5 (2I ----------> I2 + 2e)

RedOx: 2IO3 + 10I + 12H+ ----------> 6I2 + 6H2O

Now, since all coefficients are multiple of 2, we can divide all reaction by 2 to get the final answer as:
RedOx: IO3 + 5I + 6H+ ----------> 3I2 + 3H2O