Question #d0d05

1 Answer
Oct 6, 2015

#16x+40y-5y^2=48#

Explanation:

If the axis of symmetry of a parabola is parallel to the X-axis then the vertex form of the equation is
#color(white)("XXX")x=m(y-b)^2+a# with the vertex at #(a,b)# for some constant #m#

Given the vertex at #(-2,4)#
this becomes
#color(white)("XXX")x=m(y-4)^2+(-2)#

Since this equation has a solution #(x,y)=(3,8)#
we have
#color(white)("XXX")3=m(8-4)^2-2 #color(white)("XXX")16m=5
#color(white)("XXX")m=5/16

So the equation is
#color(white)("XXX")x=5/16(y-4)^2-2#

Which could be simplified in various forms:
#color(white)("XXX")16x=5(y^2-8y+16)-32#

#color(white)("XXX")16x=5y^2-40y+48#

#color(white)("XXX")16x+40y-5y^2=48#
graph{16x+40y-5y^2-48=0 [-4.07, 8.414, 2, 8.5]}