Question

Question #72f18

Answer 1

See the explanation below.

Explanation:

There is no "rate of change on `(-6,2)`".

The average rate of change of a function `f` on an interval `[a,b]` is

`(f(b)-f(a))/(b-a)`

So for example, given a function like `f(x)=x^2+5`, we can find the average rate of change on `[-6,2]` by finding

`(f(2)-f(-6))/(2-(-6)) = ((9)-(41))/8 = -32/8 = -4`