How many #sf(OH^-)# ions are present in 5.0 ml of 0.3M #sf(Ba(OH)_2)# solution ?

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Answer 1 · 2015-09-26T12:27:18

#1.8xx10^21#

1 mole barium hydroxide produces 2 moles hydroxide ions:

#rarrBa_((aq))^(2+)+2OH_((aq))^-#

#c=n/v#

#n=cxxv#

so no. moles #OH^(-) = 2xx0.3xx0.005=0.003"mol"#

Multiplying by #L# The Avogadro Constant:

#=6.02xx10^(23)xx0.003=1.8xx10^(21)# ions.

This ignores the small amount present from the ionisation of water.