Question #77828

1 Answer
Nghi N.
Oct 1, 2015

Solve: #(3 - 4sin^2 x)sin x = 0#
Ans: #x = 0, pi/3; (2pi)/3; pi;(4pi)/3; (5pi)/3 and 2pi#

Explanation:

#(3 - 4sin^2 x)sin x = 0#
a. #sin x = 0# --> x = 0 and #x = pi# and #x = 2pi#
b. #3 - 4sin^2 x = 0 sin^2 x = 3/4#
#sin x = +- sqrt3/2#
#sin x = sqrt3/2# --> #x = pi/3# and #x = (2pi)/3#
#sin x = -sqrt3/2# --> #x = (4pi)/3# and #x = (5pi)/3#

Related questions
Impact of this question
146 views around the world
You can reuse this answer
Creative Commons License