Question

Question #e6807

Answer 1

I found ii)

Explanation:

We can write:
`A=B^n*C^m` as:
`LT=(L^2T^-1)^n*(LT^2)^m`
`LT=L^(2n)T^(-1n)*L^mT^(2m)` and:
`LT=L^(2n+m)T^(-n+2m)`
So to have the two sides equal we need that:
`2n+m=1`
`-n+2m=1`
from the second: `n=2m-1`
into the first:
`2(2m-1)+m=1`
`4m-2+m=1`
and:
`5m=3`
`m=3/5`
and back into `n=2m-1` you get:
`n=6/5-1=1/5`