Question #3e289

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Answer 1 · 2015-10-06T02:20:05

#x=(-1+sqrt(3)i)/2,# #(-1-sqrt(3)i)/2#

#x^2+x+1# is a quadratic equation in the form #ax^2+bx+c#, where #a=1, b=1, c=1#

This equation can be factored using the quadratic formula.

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Substitute the values for a, b, and c.

#x=(-1+-sqrt(1^2-(4*1*1)))/(2*1)=#

#x=(-1+-sqrt(1-4))/2=#

#x=(-1+-sqrt-3)/2=#

#x=(-1+-sqrt(3)i)/2#

#x=(-1+sqrt(3)i)/2,# #(-1-sqrt(3)i)/2#