Question #2e551

1 Answer
Oct 20, 2015

Answer:

8.39 grams #HCl# will react with 5.00 grams of #MnO_2#

Explanation:

#4HCl + MnO_2 -> 2H_2O + MnCl_2 + Cl_2#

For this reaction determine the mass of HCl that will react with
5.00 grams of manganese dioxide.

This is a basic stoichiometry problem of mass to mass conversions.

# "grams" -> "moles" -> "moles" -> "grams"#

Mass of #MnO_2 = 54.94 + 2(15.99) = "86.92 g MnO"_2#
Mass of #HCl = 1.01 + 35.45 = "36.46 g HCl"#

#5.00 cancel("g MnO"_2) xx (1 cancel("mol MnO"_2))/(86.92 cancel("g MnO"_2)) xx (4 cancel("mol HCl"))/(1cancel("mol MnO"_2)) xx "36.46 g HCl"/(1 cancel("mol HCl"))#

The middle conversion factor is the mole to mole ratio from the balance chemical equation of #"4 mol HCl"# for #"1 mol MnO"_2#

#((5.00) (4) (36.46))/(86.92)#

#"8.39 grams HCl"#

Here is a gram to gram video explanation.

http://bit.ly/1kljEVR