Find the molar quantity of #BCl_3# in #1.51*g# of this substance. What is the mass, and molar quantity of boron here?

1 Answer
anor277
Oct 12, 2015

Find the molar quantity of #BCl_3# in #1.51*g# of this substance. This molar quantity is also the molar quantity of boron.

Explanation:

Molar quantity of #BCl_3#:

#(1.51*g)/((10.81+3xx35.45)*g*mol^-1)# #=# #?? mol#.

This molar quantity is precisely the same as the molar quantity of boron, because for every mol boron trichloride, there are 1 mol of boron of 3 mol of chloride. Is this clear?

If this is clear, then how many moles of #Cl# are present?

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