Here's how you could do that.
Judging from the amount of information given, I will have to make some assumptions in order to be able to provide an answer.
Let's assume that you set the volume of the
#C = n/V implies n = C * V#
#n = "0.45 M" * "1 L" = "0.45 moles"#
of sodium lactate.
Use the compound's molar mass to determine how many grams would contain this many moles
#0.45color(red)(cancel(color(black)("moles"))) * "112.06 g"/(1color(red)(cancel(color(black)("mole")))) = "50.43 g"#
Now use the sodium lactate's known percent concentration to find how many grams of
#50.43color(red)(cancel(color(black)("g sodium lactate"))) * "100 g solution"/(50color(red)(cancel(color(black)("g sodium lactte")))) = "100.86 g solution"#
So, to prepare a
As practice, you can redo the calculations for different volumes of the final solution.
A different volume of the final solution would affect the number of moles of sodium lctate it must contain, which in turn will affect the mass of the