Question #2a59b
1 Answer
Nov 1, 2015
51.708 N
Explanation:
resolving the weight in components,
force acting along the plane (driving force)=Mgsin(theta)=51.708N
M=8.6Kg; theta=37.8 degrees and g= 9.81
normal force= Mgcos(theta)=66.66
max static friction(since the body is at rest initially we use static friction)= coeff of static friction normal force=1.43*66.66=95.037:
which is more than driving force.
hence the body remains at rest and the frictional force is equal to the driving force for the equilibrium of body.
