# Question 6367d

Dec 9, 2015

$\textcolor{g r e e n}{4.9 \textcolor{w h i t e}{.} \text{gallons used in 7 minutes}}$

#### Explanation:

This is a ratio problem that is best solved in the format of: $\frac{a}{b}$ rather than $a : b$

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As we are looking to solve for water we use that as the numerator:

Let gallons be $\textcolor{b l u e}{g}$
Let time in minutes be $\textcolor{b l u e}{m}$
Let the unknown amount of water be $\textcolor{b l u e}{x}$

$\left(\text{water used")/("time used}\right) \to \frac{\textcolor{b r o w n}{16.8} \textcolor{b l u e}{g}}{\textcolor{b r o w n}{24} \textcolor{b l u e}{m}}$

Write as :

$\frac{\textcolor{b r o w n}{16.8} \textcolor{b l u e}{g}}{\textcolor{b r o w n}{24} \textcolor{b l u e}{m}} = \frac{\textcolor{b r o w n}{x}}{\textcolor{b r o w n}{7} \textcolor{b l u e}{m}}$

$\textcolor{b r o w n}{x = \frac{16.8 \times 7}{24}} \times \textcolor{b l u e}{\frac{g \times m}{m}}$

$\textcolor{b r o w n}{x = 4.9} \times \textcolor{b l u e}{g}$

$\textcolor{g r e e n}{x = 4.9 g}$