# Question #e8863

##### 2 Answers

The volume of 0.00988 moles of Oxygen @ STP = 224.5 ml

#### Explanation:

Since the condition is at STP, therefore the value of P = 0.98692 atm, T= 273.15 K and the R = 0.0821 li- atm/mole-K. The no. of moles of Oxygen is given as 0.00988 moles.

Using the Ideal Gas Law:

PV = nRT , divide both sides by P to isolate the V

V = nRT/P, the desired formula, then substitute the given data

V = {0.00988

V = 0.2215519 li/0.98692

V = 0.2244882 li, convert to ml

V = 224.5 ml, the volume of 0.00988 moles of Oxygen at STP

The volume of oxygen gas is

#### Explanation:

Use the ideal gas law to answer this question. The equation for the ideal gas law is

**Given/Known**

**Unknown**

Volume in mL

**Solution**

Rearrange the equation to isolate

**Convert 0.224 L to mL**