Question #98df5

1 Answer
Nov 24, 2015

Answer:

#11.26g# of Glucose.

Explanation:

Glucose #C_6H_12O_6# has a molar mass of #180.16 g/"mol"#.

From the molarity (#C_M#) and the volume (#V#) we can calculate the number of mole of glucose that will be present in the solution:

#C_M=n/V=>n=C_MxxV=0.25"mol"/cancel(L)xx0.25cancel(L)=0.0625mol#

Using the number of mole expression #n=m/(MM)# we can calculate the mass of glucose needed to be used:

#m=nxxMM=0.0625cancel(mol)xx180.16g/(cancel(mol))=11.26g#

Therefore, you will have to add #11.26g# of glucose to a #250mL#-volumetric flask then add water to the mark.

Here is a video that explains in details how you prepare a solution along with the calculations.

Lab Demonstration | Solution Preparation & Dilution.

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