How do you solve #16^x = x^2# ?
2 Answers
Nov 26, 2015
Took it up to a point beyond which I did not know how to mathematically resolve.
Explanation:
Given:
To get rid of the
~~~~~~~~~~~~~~~~~~~~~~~~~~~
You could do:
But I have idea where this would take you!
Nov 26, 2015
Explanation:
The graph of
#16^(-1/2) = 1/sqrt(16) = 1/4 = (-1/2)^2#
graph{(y-x^2)(y-16^x) = 0 [-5.313, 4.687, -0.7, 4.3]}