# Question #6a5d8

##### 1 Answer

#### Explanation:

So, you know that your target solution has a total mass of

What that means is that **every** **must contain** *per*

So, you know that

#color(blue)("% w/w" = "mass of solute"/"mass of solution" xx 100)#

If

# ( x )/"560 g" xx 100 = 65%#

The value of

#x = (65 * "560 g")/100 = "364 g"#

Since the total mas of the solution is equal to

#m_"sol" = m_"solute" + m_"solvent"#

#m_"water" = "560 g" - "364 g" = "196 g"#

Therefore, if you mix