How do we solve a redox equation when BASIC conditions are specified?
I only speak for myself, but I always solved the redox equation under acidic conditions. If basic conditions were specified, I could simply add the appropriate number of hydroxide ions to BOTH sides of the equation.
What the devil do I mean by the above spray? I will try an example. Consider the oxidation of chromium(III) hydroxide,
Now clearly, both charge and mass are balanced (and they MUST be!), however, basic conditions were specified, so how can I include the
On each side of the equation there is 1 metal atom,