# Question #32f25

Sep 10, 2016

$1.8 \times {10}^{6} P a$, rounded to one decimal place.

#### Explanation:

We know that pressure $P$ is force applied perpendicular to the surface of an object per unit area.
Since we are to calculate pressure in Pascals which is SI unit of pressure, we may convert given quantities in respective SI units.

1. $1 l b = 0.453592 k g$
Given weight (read mass here) of woman$= 130 \times 0.453592 \approx 59 k g$
2. $1 i {n}^{2} = 0.00064516 {m}^{2}$
Area of heel$= 0.50 \times 0.00064516 = 0.00032258 {m}^{2}$

Now Force applied$= m g = 59 \times 9.81 = 578.79 N$,
Here $g$ is acceleration due to gravity.
Pressure $P = \frac{578.79}{0.00032258} = 1.8 \times {10}^{6} P a$, rounded to one decimal place.