Question

Question #9c03e

Answer 1

9.72atm

Explanation:

Given

`V_1 ->"Initial volume of air"=400cm^3`

`P_1 ->"Initial pressure air"= 1atm`

`T_1 ->"Initial temperature air"= 15+273=288K`

`V_2 ->"Final compressed volume of air"=50cm^3`

`T_2 ->"Final temperature air"= 77+273=350K`

`P_2 ->"Initial pressure air"=?`

Now we have combined Boyle's and Charle's law relation as

`(P_2V_2)/T_2=(P_1V_1)/T_1`

`=>(P_2*50)/350=(1*400)/288`

`P_2=(8*350)/288=9.72atm`