# Question 19987

Dec 15, 2015

$\text{90 g}$

#### Explanation:

You need your target solution to have a concentration of $\text{0.6 g/mL}$, which means that every milliliter of solution must contain $\text{0.6 g}$ of sugar.

Simply put, you need to make sure that you dissolve enough sugar in that $\text{150-mL}$ sample of water to ensure that every milliliter of solution will contain $\text{0.6 g}$ of sugar.

Well, if you need $\text{1 mL}$ to contain $\text{0.6 g}$, then $\text{150 mL}$ must contain

150 color(red)(cancel(color(black)("mL solution"))) * overbrace("0.6 g sugar"/(1color(red)(cancel(color(black)("mL solution")))))^(color(blue)("given concentration")) = color(green)("90 g sugar")#

You can dissolve about $\text{2 g}$ of sugar per milliliter of water at room temperature, so you could prepare this solution by dissolving $\text{90 g}$ of sugar in about $\text{100 mL}$ of water, then adding enough water to get the final volume of the solution to $\text{150 mL}$.