568 mL of Chlorine 25 C will occupy what volume at -25 C while the pressure remains constant?

1 Answer
Phiri
May 3, 2018

#"473mL"#

Explanation:

Using the combined gas law that states that #(P_1V_1)/T_1 = (P_2V_2)/T_2#

Since our pressure remains constant, we can eliminate P, leaving us with #V_1/T_1 = V_2/T_2#

We need our T to be in Kelvin. To convert Celsius to Kelvin, add 273.

#T_1 = 25 + 273 = 298K#
#T_2 = -25 + 273 = 248K#

Now let's plug in values.

#"568mL"/"298K" = V_2/"248K"#

Isolate #V_2# by cross multiplying and dividing.

#"568mL" * "248K" =V_2 "298K"#

#("568mL" * "248K")/ "298K" = V_2#

Our K's cancel, leaving us with #("568mL" * 248)/ 298 = V_2#

After calculating and using sig figs, we're given #"473mL"#

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