568 mL of Chlorine 25 C will occupy what volume at -25 C while the pressure remains constant?

1 Answer
May 3, 2018

"473mL"

Explanation:

Using the combined gas law that states that (P_1V_1)/T_1 = (P_2V_2)/T_2

Since our pressure remains constant, we can eliminate P, leaving us with V_1/T_1 = V_2/T_2

We need our T to be in Kelvin. To convert Celsius to Kelvin, add 273.

T_1 = 25 + 273 = 298K
T_2 = -25 + 273 = 248K

Now let's plug in values.

"568mL"/"298K" = V_2/"248K"

Isolate V_2 by cross multiplying and dividing.

"568mL" * "248K" =V_2 "298K"

("568mL" * "248K")/ "298K" = V_2

Our K's cancel, leaving us with ("568mL" * 248)/ 298 = V_2

After calculating and using sig figs, we're given "473mL"