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Answer 1 · 2016-02-28T23:29:40

You need 1.07 kJ of energy to melt 3.2 g of ice at 0 °C.

The formula for the energy needed is

#q =mΔH_"fus"#, where

#q# is the heat energy required

#m# is the mass of the ice

#ΔH_"fus"# is the enthalpy of fusion (i.e. the energy required to melt 1 g of ice)

For ice, #ΔH_"fus" = "333.55 J /g"#

Hence,

#q = 3.2 color(red)(cancel(color(black)("g ice"))) × "333.35 J"/(1 color(red)(cancel(color(black)("g ice")))) = "1070 J" = "1.07 kJ"#