Question

Question #44100

Answer 1

`=11.25m`

Explanation:

From given graph we see that the two vehicles retarded uniformly to zero velocity.

The area under each v-t graph is the measure of the distance traversed . So total area is the total distance traversed after the application brakes at t=0.

Total distance `=(1/2xx10xx2.5+1/2xx15xx3.5)m=(12.5+26.25m)`

`=38.75m`

At =0 the distance between the vehicles is `15-(-35)m=50m`

So when the two vehicles will come to rest the distance of separation between them will be `=(50-38.750m=11.25m`