# Question 44100

Jul 9, 2016

$= 11.25 m$

#### Explanation:

From given graph we see that the two vehicles retarded uniformly to zero velocity.

The area under each v-t graph is the measure of the distance traversed . So total area is the total distance traversed after the application brakes at t=0.

Total distance $= \left(\frac{1}{2} \times 10 \times 2.5 + \frac{1}{2} \times 15 \times 3.5\right) m = \left(12.5 + 26.25 m\right)$

$= 38.75 m$

At =0 the distance between the vehicles is $15 - \left(- 35\right) m = 50 m$

So when the two vehicles will come to rest the distance of separation between them will be =(50-38.750m=11.25m#