Question #9abd1

1 Answer
May 25, 2016

#"The vertex will be at the point " (-1, \ 4)#

Explanation:

#"Rearrange the formula so that it fits the parabola equation"#

# y= a( x- h)^2+k#

#"The vertex will be at the point" (\ h, \ k)#

#"To rearrange the equation, add one and subtract one"#

#y=-x^2-2x-color(red)1+3+color(red)1#

#y=(-x^2-2x-color(red)1)+3+color(red)1#

#y=-1*(x^2+2x+1)+4#

#y=-1*(x+1)^2+4#

#y=-1*(x-(color(red)(-1)))^2+color(red)4#

#h=-1 " and " k=4#

#"The vertex will be at the point " (-1, \ 4)#

#""#

#"The " x "- intercept is at " x=-3 " and " x=1 "#

#"The " y "- intercept is at " y=3 #

graph{-x^2-2*x+3 [-8.77, 6.94, -2.18, 5.675]}