Question #7b172

1 Answer
May 25, 2016

There are #360# different word codes.

Explanation:

Three I's together positioned within a word of #8# letters can take one of #6# positions:
#123, 234, 345, 456, 567, 678#

Let's count the combinations of other letters for a fixed position of three I's and multiply it by #6#, according to positioning of three I's.

Remaining #5# places are taken by letters D, E, N and two letters T. These letters can be permuted in #5!# different ways, however, we have to divide this number by #2# since exchanging the places between two identical letters T would not change the resulting word.

So, the number of different combinations of D, E, N and two letters T is #(5!)/2 = 60#.
Multiplied by the number of positions of three I's together, the total number of different combinations is #60*6=360#.