How many copper atoms in a mass of #0.595*g# of copper?

1 Answer
Jan 21, 2016

Answer:

Avogadro's number of copper atoms has a MASS of #63.55# #g#. If you didn't know that, then where would we find it?

Explanation:

If we write #N_A# #=# #6.022xx10^(23)# #mol^-1#. Then we can estimate the number of copper atoms based on the MASS of the copper atoms.

So we need the proportion of #1# #"mole"# that #0.595# #g# represents.

#(0.595*g)/(63.55*g*mol^-1)# #=# #??# #mol#.

You then multiply this number by #N_A# to get the NUMBER of copper atoms.