# How many copper atoms in a mass of 0.595*g of copper?

Jan 21, 2016

Avogadro's number of copper atoms has a MASS of $63.55$ $g$. If you didn't know that, then where would we find it?

#### Explanation:

If we write ${N}_{A}$ $=$ $6.022 \times {10}^{23}$ $m o {l}^{-} 1$. Then we can estimate the number of copper atoms based on the MASS of the copper atoms.

So we need the proportion of $1$ $\text{mole}$ that $0.595$ $g$ represents.

$\frac{0.595 \cdot g}{63.55 \cdot g \cdot m o {l}^{-} 1}$ $=$ ?? $m o l$.

You then multiply this number by ${N}_{A}$ to get the NUMBER of copper atoms.