How do logarithms work?

1 Answer
Jan 24, 2016

See explanation...

Explanation:

Logarithms work because exponents work...

In general #10^a * 10^b = 10^(a+b)#

This is easier to see in the case where #a# and #b# are positive whole numbers:

#10^a xx 10^b = stackrel "a times" overbrace(10xx10xx...xx10) xx stackrel "b times" overbrace(10xx10xx...xx10)#

#=stackrel "a+b times" overbrace(10xx10xx...xx10) = 10^(a+b)#

but it works for any Real numbers #a# and #b#.

If #x = 10^a# then we call #a# the common logarithm of #x#.

To say that #x = 10^a# and #y = 10^b# is the same as saying
#a = log_10 x# and #b = log_10 y# and we find:

#log_10 x + log_10 y = log_10 (xy)#

since:

#10^(a + b) = 10^a * 10^b#