Question

Question #7c971

Answer 1

C

Explanation:

As shown in the above picture, if we have two metal plates carrying charge density `sigma` and the distance between the plates is `d` then the
Electric field between the plates `E=sigma/epsilon_0`,
where `epsilon_0` is a physical constant and is called permittivity of free space. It has a value `approx 8.854 xx 10^−12 F·m^(−1)` (farads per metre). WE have neglected the edge effect and assumed the plates to be infinite.

or `E=V/d`, where `V` is the voltage difference between the plates.

Graphically this is represented by C in the question.