What is the number of ethyl alcohol molecules in a #22.26*g# mass?

1 Answer
anor277
Feb 6, 2016

Approx. half a mole. Therefore approx. #1/2# Avogadro's number.

Explanation:

Moles of ethanol #=# #(22.26*g)/(46.07*g*mol^-1)#. This molar quantity represents a fraction of Avogadro's number.

In #1# #mol# of stuff there are #N_A# individual items of that stuff, where #N_A# #=# #6.022xx10^23#.

So the answer #=# #(22.26*cancel(g))/(46.07*cancel(g)*cancel(mol^-1))# #xx# #6.022xx10^23*cancel(mol^-1)# #=# #??#

We get a dimensionless number, as is required for a number.

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