Question

What is the number of ethyl alcohol molecules in a `22.26*g` mass?

Answer 1

Approx. half a mole. Therefore approx. `1/2` Avogadro's number.

Explanation:

Moles of ethanol `=` `(22.26*g)/(46.07*g*mol^-1)`. This molar quantity represents a fraction of Avogadro's number.

In `1` `mol` of stuff there are `N_A` individual items of that stuff, where `N_A` `=` `6.022xx10^23`.

So the answer `=` `(22.26*cancel(g))/(46.07*cancel(g)*cancel(mol^-1))` `xx` `6.022xx10^23*cancel(mol^-1)` `=` `??`

We get a dimensionless number, as is required for a number.