# You are given quantities of aluminum sulfate, Al_2(SO_4)_3, and sulfuric acid, H_2SO_4. If there are EQUAL numbers of SULFUR atoms with respect to each salt, what is the ratio of oxygen atoms...Al_2(SO_4)_3:H_2SO_4?

If the number of sulfur atoms are EQUAL, then the ratio of oxygen atoms, ($A {l}_{2} {\left(S {O}_{4}\right)}_{3} : {H}_{2} S {O}_{4}$) $=$ $1 : 1$
It is given that both salts contain the same number of sulfur atoms. Thus we have $A {l}_{2} {S}_{3} {O}_{12}$, and necessarily $3$ $\times$ ${H}_{2} S {O}_{4}$. There are $3$ $\text{equiv}$ sulfuric acid per equiv aluminum sufate, and necessarily $\text{12}$ $\text{equiv}$ of $O$ atoms in the acid. And (if I have been doing my sums correctly), the ratio of oxygens is $1 : 1$.