Question

What is the volume of `150.0*"gallons"` in `"litres"`?

Answer 1

Here, I assume that the `"gallon"` `=` `4.800*L`

Explanation:

So to the calculation:

`(150.0cancel" gallons" xx 4.8*cancelL*cancel("gallon"^-1))/(25.0xx10^-3*cancelL)` `= ??`

I get a large dimensionless number.

I have used an Imperial gallon here (equivalent to `8` `"pints"`, `4800` `mL`). A US gallon (= `3.785` `L`) will of course give a different result. I don't know which gallon you are using, and this is a good illustration of the inutility of NON SI units.