Question

Question #6965d

Answer 1

Hydrogen at the cathode.

Oxygen at the anode.

Explanation:

At the -ve cathode water molecules are reduced:

`2H_2O_((l))+2erarrH_(2(g))+2OH_((aq))^-`

`Na^+` ions are also attracted but are not discharged as this requires much more energy in comparison to discharging water.

At the +ve anode `OH^-` ions are attracted and discharged:

`4OH_((aq))^(-)rarrO_(2(g))+2H_2O_((l))+4e`

You will also get water molecules being oxidised:

`2H_2O_((l))rarrO_(2(g))+4H_((aq))^(+)+4e`