Question #5d4cd

1 Answer
May 7, 2016

#g(t)=y=2#

Explanation:

Just to make sure about something. The term #g(t)# is just a way of identifying a particular formula structure. Also the fact that the formula structure is going to be applied to the variable #t#

Given: #g(t)=3/2t-5/2#

For this question: wherever there is a variable #t# substitute the value of 3

Write as: # y=3/2t-5/2#

#color(brown)(y=3/2t-5/2)color(blue)(" " ->" " y= 3/2(3)-5/2#

#y=9/2-5/2" " =" " (9-5)/2" "=" "4/2" "=" "2#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Foot note")#

If you had #g(s)# you would write#" " 3/2s-5/2#

So if you had #g(t)-g(s)# you would write #(2/3t-5/2)-(2/3s-5/2)#