Question

Question #627e5

Answer 1

4%

Explanation:

We know, Time period (T) of a simple pendulum is related with
acceleration due to gravity (g)and length of the pendulum(l)
as follows
`T=2pisqrt(l/g)`

Squaring and rearranging we get

`g=4pi^2l/T^2`

Taking log we get

`logg=log4+2logpi+logl-2logT`

Differentiating we have

`(Deltag)/g=(Deltal)/l-2(DeltaT)/T`

Maximum error

`((Deltag)/g)_"max"%=(Deltal)/l%+2(DeltaT)/T%`

`((Deltag)/g)_"max"%=2+2*1=4`