Question #e0678

Nov 25, 2017

Here's what I get.

Explanation:

You start by drawing alternating $\text{S}$ and $\text{N}$ atoms in a four-membered ring.

Then you add the remaining valence electrons to give every atom an octet.

You find that you must put one double bond into the ring.

Since you can put it in four different places, there are four resonance contributors.