# Question #0f0e4

Take side limits you get

${\lim}_{x \to {3}^{+}} \frac{{x}^{3} - 8}{{x}^{2} + x - 12} = + \infty$

and

${\lim}_{x \to {3}^{-}} \frac{{x}^{3} - 8}{{x}^{2} + x - 12} = - \infty$

Hence side-limits are different the limit does not exist.

The graph of f(x) near x=3 is