# At "STP", how many molecules would there be in a 3.28*L volume of H_2S(g)?

Mar 5, 2016

#### Answer:

The molar volume of an ideal gas is $22.4$ $L$ at $S T P$.

#### Explanation:

We idealize the behaviour of hydrogen sulfide, and take the quotient:

$\text{Volume of } {H}_{2} S$ $=$ $\frac{3.28 \cdot L}{22.4 \cdot L \cdot m o {l}^{-} 1}$ $=$??mol.

Now $1$ mole of gas contains ${N}_{A}$ (6.022xx10^23*mol^-1) particles, so:

$\text{No. of molecules}$ $=$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1 \times \frac{3.28 \cdot L}{22.4 \cdot L \cdot m o {l}^{-} 1}$ $=$

??H_2S" particles?"

How smelly would such a quantity of hydrogen sulfide be? You would probably pass out!