Question #a4647

1 Answer
Mar 4, 2016

(a) #1.0xx10^13erg#

Explanation:

Work done in SI system of units#=1 text{ mega joule}#
Since mega#=10^6#, hence Work done #1.0xx10^6J#

We need to convert Joule to, CGS system of units where erg is the unit of work, dyne is the unit of Force and centimetre is the unit of distance.
Now #1J=1Nxx1m=10^5dyn e color (red)diamondxx100 cm=10^7erg#
#color (red)diamond# Force#=ma#
#1N=1kgxx1ms^-2=1000gmxx100cms^-2=10^5dyn e#

In the given problem
#1.0xx10^6J=1.0xx10^6xx10^7#
#=1.0xx10^13erg#