Question #fe34c

1 Answer

Answer:

You will have 10 moles of #"HBr"#, limited by the 5 moles of hydrogen gas.

Explanation:

I believe this is an incomplete question, but based on the information given I would assume you are trying to find the number of moles of product produced.

#"H"_2 + "Br"_2 -> 2"HBr"#

#5 cancel("mol H"_2) xx "2 mol HBr"/(1 cancel("mol H"_2)) = "10 mol HBr"#

#7 cancel("mol Br"_2) xx "2 mol HBr"/(1 cancel("mol Br"_2)) = "14 mol HBr"#

So, 5 moles of #"H"_2# limit the production of #"HBr"#, as you see from above, 10 moles of #"HBr"# are produced.

It is like cooking. If a recipe calls for seven eggs, and you only have five, the eggs limit the amount of product produced.