# Question fe34c

Apr 1, 2016

You will have 10 moles of $\text{HBr}$, limited by the 5 moles of hydrogen gas.

#### Explanation:

I believe this is an incomplete question, but based on the information given I would assume you are trying to find the number of moles of product produced.

$\text{H"_2 + "Br"_2 -> 2"HBr}$

5 cancel("mol H"_2) xx "2 mol HBr"/(1 cancel("mol H"_2)) = "10 mol HBr"

7 cancel("mol Br"_2) xx "2 mol HBr"/(1 cancel("mol Br"_2)) = "14 mol HBr"#

So, 5 moles of ${\text{H}}_{2}$ limit the production of $\text{HBr}$, as you see from above, 10 moles of $\text{HBr}$ are produced.

It is like cooking. If a recipe calls for seven eggs, and you only have five, the eggs limit the amount of product produced.