Question

Question #fe34c

Answer 1

You will have 10 moles of `"HBr"`, limited by the 5 moles of hydrogen gas.

Explanation:

I believe this is an incomplete question, but based on the information given I would assume you are trying to find the number of moles of product produced.

`"H"_2 + "Br"_2 -> 2"HBr"`

`5 cancel("mol H"_2) xx "2 mol HBr"/(1 cancel("mol H"_2)) = "10 mol HBr"`

`7 cancel("mol Br"_2) xx "2 mol HBr"/(1 cancel("mol Br"_2)) = "14 mol HBr"`

So, 5 moles of `"H"_2` limit the production of `"HBr"`, as you see from above, 10 moles of `"HBr"` are produced.

It is like cooking. If a recipe calls for seven eggs, and you only have five, the eggs limit the amount of product produced.