Question

Question #8ed5a

Answer 1

`(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}`

Explanation:

`f(x) = sum_{i=0}^n a^i x^{n-i}`
so deriving
`(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}`